Term: 2nd Term
Week: 5
Class: Senior Secondary School 3
Age: 17 years
Duration: 40 minutes of 2 periods each
Date:
Subject: Computer studies and ICT
Topic:- Basic operations with binary numbers
SPECIFIC OBJECTIVES:
At the end of the lesson, pupils should be able to
INSTRUCTIONAL TECHNIQUES: Identification, explanation, questions and answers, demonstration, videos from source
INSTRUCTIONAL MATERIALS: Videos, loud speaker, pictures, Data Processing for senior Secondary Education by Hiit Plc, WAPB Computer Studies for Senior Secondary III by Adekunle et al, On-line Materials.
INSTRUCTIONAL PROCEDURES
PERIOD 1-2
PRESENTATION |
TEACHER’S ACTIVITY |
STUDENT’S ACTIVITY |
STEP 1 INTRODUCTION |
The teacher reviews the previous lesson on octal and hexadecimal number bases |
Students pay attention |
STEP 2 EXPLANATION |
He explains the rules for adding and subtracting binary numbers and solves some examples
|
Students pay attention and participates |
STEP 3 DEMONSTRATION |
He then explains the rules of multiplying and dividing binary numbers and solves some examples |
Students pay attention and participate |
STEP 4 NOTE TAKING |
The teacher writes a summarized note on the board |
The students copy the note in their books |
NOTE
BASIC OPERATIONS ON BINARY NUMBERS
ADDITION OF BINARY NUMBERS
We can add binary numbers in the same way as we separate with ordinary base 10 numbers.
The identities to remember are:-
0 + 0 = 0,
0 + 1 = 1,
1 + 0 = 1,
1 + 1 = 10,
1 + 1 + 1 = 11,
1 + 1 + 1 + 1 = 100
The identities to remember on subtraction are:
0 – 0 = 0,
1 – 0 = 1,
10 – 1 = 1,
11 – 1 = 10,
100 – 1 = 11
In multiplication,
0 x 0 = 0,
1 x 0 = 0,
1 x 1 = 1.
When there is long multiplication of binary numbers, the principle of addition can be used to derive the answer. Under division, the principle of subtraction can be used.
EXAMPLES
110
× 110
000
110
+ 110
100100
111100
101 = 110
EVALUATION: 1. Explain the basic rules for these operations in binary
2i. Solve the following exercises
a. 101 + 11 =
b. 111 + 111 =
c. 1010 + 1010 =
d. 11101 + 1010 =
e. 11111 + 11111 =
ii.
iii.
iv.
CLASSWORK: As in evaluation
CONCLUSION: The teacher commends the students positively