Term: 3^{rd} Term
Week: 9
Class: Senior Secondary School 1
Age: 15 years
Duration: 40 minutes of 5 periods each
Date:
Subject: Physics
Topic: Motion
SPECIFIC OBJECTIVES: At the end of the lesson, pupils should be able to
INSTRUCTIONAL TECHNIQUES: Identification, explanation, questions and answers, demonstration, videos from source
INSTRUCTIONAL MATERIALS: Videos, loud speaker, textbook, pictures
INSTRUCTIONAL PROCEDURES
PERIOD 12
PRESENTATION 
TEACHER’S ACTIVITY 
STUDENT’S ACTIVITY 
STEP 1 INTRODUCTION 
The teacher reviews the previous lesson on vector resolution 
Students pay attention 
STEP 2 EXPLANATION 
He states the equations of motion

Students pay attention and participates 
STEP 3 DEMONSTRATION 
He solves some examples involving the equations of motion

Students pay attention and participate 
STEP 4 NOTE TAKING 
The teacher writes a summarized note on the board 
The students copy the note in their books 
NOTE
MOTION
SPEED: This is the rate of change distance with time
Speed = 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒
𝑡𝑖𝑚𝑒
VELOCITY: This is the rate of change of displacement with time
Velocity = 𝑑𝑖𝑠𝑝𝑙𝑎𝑐𝑒𝑚𝑒𝑛𝑡
𝑡𝑖𝑚𝑒
ACCELERATION: This is the rate of change of velocity with time
Acceleration= 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦
𝑡𝑖𝑚𝑒
EQUATIONS OF MOTION
Example:
A car travelling at 54kmh1 slows down uniformly to a velocity of 18kmh1 when the brakes were gradually applied
(a) how long does it take to cover a distance of 50m.
(b)What is the deceleration?
Solution:
a.) Initial velocity, U = 54kmh^{1} = 15ms^{1} Final velocity, V =18kmh^{1} = 5ms^{1} Distance covered, s = 50m
S _{= }(V + U)t
2
S _{= }(15 + 5)t
2
_{ }
50 = 10t
t = 5s
b.) To determine the deceleration ( negative acceleration)
V = u + at
5 = 15 + 5t
10 = 5a
a = 2ms^{2}
Example: A body, starting from rest, travels for 30s. Determine the final velocity attained after covering a distance of 40m
Solution:
U = 0
t = 30s
S = 40m
S= ut + ½ at^{2}
40 = 0 x t + ½ x a x 30^{2}
80 = 900a
a = 0.0889m/s^{2}
The final velocity, v = u + at
V = 0 + 0.0889 x 30
V = 2.7m/s
EVALUATION: 1. How do we calculate
2. State the equations of motion
3. A Body at rest was accelerated, and it traveled for 5 minutes. The constant acceleration provided to the body was 2 m/sec^{2}. Find the final velocity the object had before coming to a stop. Also, answer the equation of motion used to find out the final velocity
4. A ball is dropped from a certain height. It took the ball 15 seconds to reach the ground. What is the height at which the ball was initially, also answer which equation of motion is used to answer this question? [Take g=10m/sec^{2}].
5. A Car with an initial speed of 1 m/sec was in motion for 10 minutes, and then it came to a stop, the velocity right before it stopped was 5m/sec. What was the constant acceleration of the car?
6. A cycle covered 2 km in 8 minutes and the initial velocity of the cycle was 1 m/sec. Find the acceleration that the cycle had in its motion.
7. A toy is accidentally dropped by a kid from his roof. The final velocity of the toy before it reached the ground was 8m/sec. Find the height of the building.
8. Find the final velocity of an object that traveled a distance of 500meter with an initial speed of 2m/sec and acceleration of the object was 0.5m/sec^{2}.
CLASSWORK: As in evaluation
CONCLUSION: The teacher commends the students positively