Term: 3rd Term
Week: 8
Class: Senior Secondary School 1
Age: 15 years
Duration: 40 minutes of 5 periods each
Date:
Subject: Physics
Topic:- Vector resolution
SPECIFIC OBJECTIVES: At the end of the lesson, pupils should be able to
INSTRUCTIONAL TECHNIQUES: Identification, explanation, questions and answers, demonstration, videos from source
INSTRUCTIONAL MATERIALS: Videos, loud speaker, textbook, pictures
INSTRUCTIONAL PROCEDURES
PERIOD 1-2
PRESENTATION |
TEACHER’S ACTIVITY |
STUDENT’S ACTIVITY |
STEP 1 INTRODUCTION |
The teacher reviews the previous lesson on vectors |
Students pay attention |
STEP 2 EXPLANATION |
He defines and explains vector resolution. He explains the methods of vector resolution
|
Students pay attention and participates |
STEP 3 DEMONSTRATION |
He explains the guidelines for finding the resultant of two or more vectors and carries out some calculations
|
Students pay attention and participate |
STEP 4 NOTE TAKING |
The teacher writes a summarized note on the board |
The students copy the note in their books |
NOTE
VECTOR RESOLUTION
The process of determining the magnitude of a vector is known as vector resolution. The two methods of vector resolution are:
Parallelogram law of vector addition states that if two vectors acting at a common point are represented in magnitude and direction by the adjacent sides of a parallelogram, their resultant is represented in magnitude and direction by the diagonal of the parallelogram drawn from their common point of intersection and direct away from that point.
Example: Two forces with magnitudes of 25N and 18N respectively are inclined at an angle of 1200 to each other. Calculate the resultant force and the angle it makes with the 18N force.
R2 = A2 + B2 – 2ABcos(1800-ϴ)
R2 = 252 + 182 – 2 x 25 x 18cos(1800-1200)
R2 = 625 + 324 – 900cos600
R2 = 499
Resultant, R = 22.34N
RESULTANT OF TWO OR MORE VECTORS BY RESOLUTION
The resultant of two or more vectors can be found by taking the following simple steps:
ΣFx
Example: Three coplanar forces act simultaneously at a point as shown below
Find the resultant of the forces and its direction with respect to x-axis.
(Take sin600 = 0.87, cos600 = 0.50
Solution:
VERTICAL COMPONENT Ry |
HORIZONTAL COMPONENT Rx |
107 sin900 |
107cos900 |
-100sin600 |
-100cos600 |
80sin00 |
80cos00 |
ΣFy= 20N |
ΣFx = 30N |
R = √302+ 202
R = √1300
R = 36.1N
Direction is given as tanϴ = ΣFy
ΣFx
tanϴ = ΣFy
ΣFx
= 20
30
ϴ = 33.7˚
EVALUATION: 1. Define vector resolution
CLASSWORK: As in evaluation
CONCLUSION: The teacher commends the students positively