SUBJECT: MATHEMATICS
CLASS: SS 3
DATE:
TERM: 2nd TERM
REFERENCE TEXT
WEEK THREE
TOPIC: Coordinate Geometry of straight lines
Gradient and Intercepts of a line
Gradient of a line of the form y = mx + c, is the coefficient of x, which is represented by m and c is the intercept on the y axis.
Example
Solution
m = 4, c = - 7,
Hence, the equation is; y =4x - 7.
Evaluation:
1.What is the gradient and y intercept of the line equation 3x -5y +10=0 ?
Gradient and One Point Form
The equation of the line can be calculated given one point (x, y) and gradient (m) by using the formula; y - y1= m(x - x1)
Example
Find the equation of the line with gradient -8 and point(3, 7).
Solution
m = - 8, (x1, y1) =(3,7)
Equation: y - 7 = - 8(x - 3)
y = -8x + 24 +7
y = -8x + 31
Evaluation:
Two Point Form:
Given two points (x1, y1) and (x2, y2), the equation can be obtained using the formula:
y2 - y1 = y - y1
x2 - x1 x - x1
Example: Find the equation of the line passing through (2,-5) and (3,6).
Solution
6 - (-5)/3 - 2 = y - (-5)/x - 2
11 = y + 5/x - 2
11(x - 2) = y + 5
11x - 22 = y + 5
y - 11x + 27 = 0
Evaluation:
1.Find the equation of the line passing through (3, 4) and (-1, -2).
2.Find the equation of the line passing through (-8, 5) and (-6, 2).
Angles between Lines
Parallel lines:
The angle between parallel lines is 00 because they have the same gradient
Perpendicular Lines:
Angle between two perpendicular lines is 900 and the product of their gradients is – 1. Hence, m1m2 = - 1
Examples:
solution:
Equation 1: y = -3x + 2, m1 = -3
Equation 2: y + 3x = 7,
y = -3x + 7, m2 = - 3
since; m1 = m2 = - 3, then the lines are parallel
solutions:
Equation 1: x = 3y + 5, make y the subject of the equation.
3y = x + 5
y = x/3 + 5/3
m1 = 1/3
Equation 2: y + 3x = 2,
y = - 3x + 2, m2 = -3
hence: m1 x m2 = 1/3 x – 3 = - 1
since: m1m2 = - 1, then the lines are perpendicular.
Evaluation: State which of the following pairs of lines are: (i) perpendicular (ii) parallel
(1) y = x + 5 and y = - x + 5 (2). 2y – 6 = 5x and 3 – 5y = 2x (3) y = 2x – 1 and 2y – 4x = 8
Angles between Intersecting Lines:
y
y = mx + c
θ x
0
The gradient of y = mx + c is tan θ. Hence m = tan θcan be used to calculate angles between two intersecting lines. Generally the angle between two lines can be obtained using: tan 0 = m2 -m1
1 + m1m2
Example: Calculate the acute angle between the lines y=4x -7 and y = x/2 + 0.5.
Solution:
Y=4x -7, m1= 4, y=x/2+0.2, m2 =1/2.
Tan O= 0.5 - 4. = -3.5/3
1 + (0.5*4)
Tan O =- 1.1667
O=tan-1(-1.1667) = 49.4
Evaluation:Calculate the acute angle between the lines y=3x -4 and x - 4y +8 = 0.
General Evaluation:
1.Calculate the acute angle between the lines y=2x -1 and 2y + x = 2.
2.If the lines 3y=4x -1 and qy= x + 3 are parallel to each other, find the value of q.
3.Find the equation of the line passing through (2,-1) and gradient 3.
Reading Assignment: NGM for SS 3 Chapter 9 page 75 – 81
Weekend Assignment
1.Find the equation of the line passing through (5,0) and gradient 3.
2.Find the equation of the line passing through (2,-1) and (1, -2).
(a) Find the gradients and intercepts on the axes of each line.
(b) Find the equation parralel to x -4y + 8=0 at the point (3, -5)
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