Coordinate Geometry of straight line: Cartesian coordinate graphs
SUBJECT: MATHEMATICS
CLASS: SS 3
DATE:
TERM: 2nd TERM
REFERENCE TEXT
WEEK TWO
TOPIC: Coordinate Geometry of straight line: Cartesian coordinate graphs
Distance between two lines:
In the figure below, the coordinates of the points A and B are (x1, y1) and (x2, y2), respectively. Let the length of AB be l.
y
B(x2, y2)
l
y2 – y1
A(x1, y1) x2 – x2 C
X
Using Pythagoras theorem:
AB2 = AC2 + BC2
l2 =(x2 – x1)2 + (y2 – y1)2
l = √(x2 – x1)2 + (y2 – y1)2
Example:
Find the distance between the each pair of points: a. (3, 4) and (1, 2) b. (3, - 3) and (- 2, 5)
Solution:
Using l =√(x2 – x1)2 + (y2 – y1)2
l = √22 + 22
l = √8 = 2√2 units
= √52 + (-8)2
= √25 + 64 = √89 = 9.43 units
Evaluation: Find the distance between the points in each of the following pairs leaving your answers in surd form: 1. (-2, - 5) and (3, - 6) 2. (- 3, 4) and (- 1, 2)
Mid-point of a line:
The mid-point of the line joining two points:
y
B(x2, y2)
y2 - y
M(x, y) D
x2 –x
y – y1
A(x1, y1) x – x1 N C
X
Triangle MAN and BMD are congruent, so AM = MD and BD = MN
x – x1 = x2 – x y – y1 = y2 – y
x + x = x2 + x1 y + y = y2 + y1
2x = x2 + x1 2y = y2 + y1
x= x2 + x1 y = y2 + y1
2 2
Hence, the mid-point of a straight line joining two is x2 + x1 ,y2 + y1
2 2
Example: Find the coordinates of the mid-point of the line joining the following pairs of points.
Solution:
Mid-point = x2 + x1 ,y2 + y1
2 2
2 2
2 2 2 2
Evaluation: Find the coordinates of the mid-point of the line joining the following pairs of points.
General Evaluation
Reading Assignment: NGM for SS 3 Chapter 9 page 77 – 78,
Weekend Assignment:
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