Lesson Notes By Weeks and Term - Senior Secondary School 2

Electromagnetic induction

SUBJECT: PHYSICS

CLASS:� SS 2

DATE:

TERM: 2nd TERM


WEEK 1

TOPIC: Electromagnetic induction

Content

Induced current

Laws of electromagnetic Induction

Induction Coil

A/C and DC Generator

Transformer and Power Transmission

Electromagnetic� induction is the production� of electric current or voltage in a conductor whenever there is a relative motion between the conductor and a magnetic field or a magnet.

The induced e.m.f. or current depends on

  1. the speed of motion of the magnet. The faster the speed of motion, the larger the induced current�
  2. the number of turns of the coil
  3. the presence of a soft-iron core inside the coil

The direction of the induced current reverses when the direction of motion of the magnet or coil is reversed.

The coil A and C are wound on a steel ring R. When the switch� S is close, a deflection will be obtained on the galvanometer G, and when S is open G will show a deflection in the opposite direction.

Current will flow in the galvanometer whenever there is relative motion between the coil and the� magnet. There is such a relative motion when the magnet moves towards the coil or away from the coil and when the magnet is stationary but the coil is moved. Such a current is called induced current and the phenomenon is called electromagnetic induction.

EVALUATION

  1. Explain the term� electro magnetic induction.
  2. Describe how induced current are produced.

Law of Electromagnetic Induction.

There are two laws of electromagnetic induction�

  1. Faraday’s law

2,� Lenz’s law

Faraday’s law of electromagnetic induction states that whenever there is a change in the magnetic lines of force (e.m.f) is induced, the strength of which is proportional to the rateof change of the flux linked with the circuit.

The magnetic flux or field lines linking a coil depends on�

  1. the magnetic field strength
  2. the number of turns of the coil
  3. the area of each turn

To obtain a large induced e.m.f. move at a high speed across a strong magnetic field. Faraday’s law gives the magnitude of the induced e.m.f.

Lenz law of electromagnetic induction states that the induced e.m.f is in such a direction as two oppose the motion or change producing it.

Lenz law gives the direction of the induced e.m.f or induced currents.

EVALUATION�

  1. State Faraday’s law of electromagnetic induction
  2. State Lenz law
  3. What are the benefits of these law to modern day engineering/

Induction Coil

This is an electrical device that is capable of producing a very high intermittent e.m.f .by electromagnetic induction from a low voltage d.c.

Source e.g battery

It consist of:

  1. a primary coil, made up of a few turns f thick� copper wire, wound on a laminated soft iron core.� The lamination of the core is to reduce loss of energy due to eddy currents.
  2. Secondary coil overlapping the primary coil. It is made up of a large number of turns of insulated thin copper wire. The ends of this coil are connected to an adjustable spark gap created by two adjustable brass rods.
  3. In front of the soft iron core of the primary coil is a make-and-break-device consisting of soft� iron armature carried on a light brass spring to which is attached a platinum contact with adjustable screw. The primary circuit is completed from this contact through a key and the battery which provide the current.

The induction coil is commonly used in motorcar ignition system and in the operation of x-ray tubes.

EVALUATION

  1. Draw a labeled diagram of the induction coil
  2. Describe the principle of operation of the induction coil.

A.C and D.C Generator.

A machine that converts mechanical energy into electrical energy or electrical energy into mechanical energy is called a dynamo. When it changes mechanical energy into electrical energy it is called a generator, but when it changes electrical energy into mechanical energy, it is called a motor.

There are two classes of generators, the alternating current (A.C) generator and the direct current (D.C) generator.

The A.C. generator consists of:

  1. � an armature – a rectangular coil consisting of a large number of turns of insulated wire�

�����wound on a laminated� soft iron core.

  1. a magnetic field created by the curved poles of a horse-shoe magnet or an���

����electromagnet.

  1. two copper slip rings to which the ends of the rectangular coil are connected and which rotate with the armature.
  2. two stationary carbon brushes which are made to pres lightly against the slip rings

EVALUATION

  1. Draw a labeled diagram of A.C generator
  2. Describe the principle of operation of A.C generator.

Direct Current ( D.C) Generator�

An a.c. generator can be made to produce a d.c by replacing the two slip rings with a single split ring or commutator. A split ring commutator is a slip ring that has been split into two segments which are insulated from each other.� The ends of the coil are connected one to each split ring or commutator segment .

The commutator is a current reverser. When the armature coil is rotated, the commutator automatically switches each end of the coil from one brush to the other each time the coil completes one-half of a revolution. As the current reverses in the coil after each half revolution, the connection between the coil and the brushes are reversed through the action of the commutator.

Transformer and Power Transmission�

A transformer is an electrical device for changing the size of an a.c. voltage. It acts to increase or decrease the em.f of an alternating current.� It consists of two separate sets of coil, the primary coil and the secondary coil.� The primary coil is the input winding of turns of wire and the secondary coil is the output winding.� The coils are wound round a soft-iron core. The soft-iron core acts to increase and concentrate the magnetic flux within the core. It is also laminated, i.e. it consists of sheets of soft-iron insulated from each other instead of a solid block of iron.� This lamination reduces loss of energy in the form of heat due to eddy currents introduced in the core.

Step down transformer

When an alternating e.m.f. or a.c voltage (EP) is applied at the terminals of the primary coil (p), an alternating magnetic flux is produced in the iron core which links or threads the secondary coil (s). An alternating e,m,f (Es) of the same frequency as that Ep is induced in the secondary coil by mutual inductance.

Mutual inductance is the flow of induced current or voltage in a coil due to an aternting� or varying current in a neighbouring coil.

The total flux linking the two coils is proportional to their number of turns. The induced e.m.f in the secondary coil (Ep) depends on the e.m.f. in the primary coil and on the ratio of the number of turns in each

:. � �ES� � ��=� ��Ns

������Ep� � � � � � Np

In an ideal transformer with a 100% efficiency, the power developed in the secondary coil is equal to the power developed in the primary coil.

:. � �Es ���=� Ip

������Ep � � � Is

Hence,� �Es� �= Ns� ���= Ip

��������������Ep� � � Np � � � Is.

To use a transformer to increase an applied� voltage, i.e to make Es greater than Ep, Ns must be grater than Np . such a transformer which increases or steps up the applied or primary voltage is called a step-up transformer. In a step-up, the primary current is greater than the secondary current but the primary voltage is less than the secondary voltage.

Energy Losses in practical transformer

There are energy losses in practical transformers due to:

  1. Eddy currents ii. Hysteresis loss,� iii. Heat loss� � iv. Leakage of magnetic flux

Eddy Current reduces efficiency because they consume power and this causes energy lost in the form of heat. Such loss can be reduced by laminating the core.

Hysteresis loss is wasted energy due to reversing the magnetization of the core.� It is reduced by the use of special alloys in the core of the primary coil.

Heat loss: the primary and secondary coils have resistance, some energy is lost in the form of heat(I2R) in the coils. This can be reduced by using thick wires or low resistance coils.

Some energy is lost due to leakage of magnetic flux. This arises because not all the lines of inductin due to current in the primary coil pass entirely through the iron core. This loss is reduced by efficient core design.

Example

  1. Find the turns ration in a transformer which delivers a voltage of 12ov in the secondary coil from a primary voltage of 60v.

��� ��� turns ration � �=� Ns � =� 120 � � �=� 2

�������������������������������������������������Np� � � � � 60

  1. A transformer has 500 turns in the primary coil and 300 turns in the secondary coil. If the primary coil is connected to a 220v mains, what voltage will be obtained from the secondary coil?� What type of transformer is this ?

��� ��� Es� � �= � Ns

������������������������Ep � � � � Np

��� ���

��� ��� Es ���=� 300

  1. 500

������������������������Es =� � �220 x 300

������������������������������������������500.

������������������������Es =� 132 v

It is a step-down transformer because secondary voltage is less than primary voltage (132 < 220)

  1. A transformer supplies 15v from a 220v mains. If the transformer� takes 0.7A from the mains when used to light three lamps connected in parallel and each rated 15v,40w, calculate:
  2. the efficiency of the transformer

ii the cost of using it for 24hrs at 30k per kwh.

Primary or input power = IpVp

��� ��� = 0.7 x 220� = 154w

secondary (output power ) =IsVs� =� (Is x 15 )w

��� p� = iv

��� p� =

������������V����

����������Is = �40

  1. = 2.67A.

Total current taken by the 3 lamps in parallel� = 3 x 2.67� =8A

:. Output power = 8 x 15� = 120 W

Efficiency� =� �Output Power� �X 100

������������������������Input Power

��� ��� = �120 � �x 100

  1. = 78%

Power consumed� = �0.7 x 220 �Kw

����������������������������������1000

Total power consumed in 24 hrs

�����������= �0.7 x 220 �x 24kwh

����������������1000.

Cost at 30k per kwh

��� = ( �0.7 x 220� �X� 24� X 30

  1. 100

������������������= N1

EVALUATION

  1. Draw a labeled diagram to explain the working of a transformer which can produce 24v from a 240v supply.
  2. Give two reasons which explains why the efficiency of the transformer cannot be 100%.

POWER TRANSMISSION

Power generated at power stations are distributed over large distances to consumers through metal cables,� Power can be transmitted either at low current and high voltage or at high current and low�

voltage .� Because the metal cables through \h which the power is transmitted have a certain amount of electrical resistance, transmitting power at high current will lead to loss of energy in the form of heat. To avoid, this power is transmitted at high voltage and low current. This is known as high tension transmission.

Low currents leads to low energy loss. It also requires thinner cables, cost of cable materials is considerably reduced if power is transmitted with low current and high voltages.

Step down transformers are used to reduce the high transmitted voltages to lower voltages required in home and factories .

Reading Assignment�

New School Physics pg 447 – 457

WEEKEND ASSIGNMENT

1, Induced current depends on the�

  1. number of turns in the coil
  2. strength of the magnet
  1. speed with which the� magnet is plunged into the coil

Which of these is/are false

(a) I only��� (b) II only � � (c) II and III only � (d) III only � � (e) None of the above.

  1. To convert an alternating current dynamo into a direct current dynamo the ;

��(a) number of turns in the coil is increased � (b) strength of the field magnet is increased��

(c ) slip rings are replaced with split rings commutator � (d ) coil is wound on a soft iron armature

  1. Which of the following devices would be used onts own in the working of a petro-driven motor car engine for obtaining a high voltage from a low one

( a) induction coil � (b) A.C dynamo � (c ) D.C generator � (d) the transformer� (e) the electric motor.

  1. A transformer with 5500turns in its primary is used between a 240v a.c supply and a 120v kettle. Calcualte the number of turns in the secondary�

���(a) 1100 � (b) 2750� � (c ) 460 � (d) 232� � (e) 10.

  1. If a current –carrying� coil is mounted on a metal frame, the back e.m.f. induced in the coil causes

��(a) inductance��� (b) Eddy current s� � (c) Electromagnetism � � (d) Dipole moment.

Theory

  1. With the aid of a diagram, describe the principle of an induction coil. Mention� two applications of this device.

1b,� State the laws f electromagnetic induction

3.Distinguish between a step-up and a step down transformer.� Give two reasons why it is preferred to�

�transmit power over long distances using a high voltage and a low current.



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