SUBJECT: PHYSICS
CLASS: SS 2
DATE:
TERM: 1st TERM
REFERENCE TEXT
WEEK TWO
TOPIC: SCALAR AND VECTOR QUANTITIES
CONTENT
CONCEPT OF SCALAR AND VECTOR QUANTITIES
Physical quantities are divided into two types
i Scalar quantity
ii Vector quantity
A scalar is one which has only magnitude (size ) but no direction e.g. distance, speed , temperature , volume , work , energy, power , mass ,electric potential , gravitational potential electric charge .
A vector quantity has both magnitude (size) and direction e.g. force, weight, velocity, acceleration, momentum displacement, magnetic flux, electric fields and gravitational fields.
Scalar quantities are added according to the ordinary rules of arithmetic. For example , a mark of 50 added to a mark of 40 produces a mark of 90 –no directional property .But a force of 50N combined with a force of 40N may produce 90N if they are acting in same direction. But they are acting in opposite direction it would produce a different result. These vectors are combined or added by a special law the parallelogram law of addition of vectors.
VECTOR REPRESENTATION
N
5cm w
ADDITION AND SUBTRACTION OF VECTORS
Two or more vectors acting on a body in a specified direction can be combined to produce a single vector having the same effect .The single vector is called the resultant.
For example:
(a) Two forces Y and X with magnitude of 3N and 4N respectively acting along the same direction will produce a resultant of 7N (algebraic sum of the two vectors).
3N + 4N = 7N
(b) If Y and X act in opposite direction, the resultant will be 1N.
4N _ 3N 1N
-
(c) If the two vectors are inclined at an angle less than 900 or more than 900 , the resultant cannot be obtained by Pythagoras theorem but by vector addition,. Parallelogram law of vector, trigonometric or scale drawings can be used to calculate the magnitude and direction of the resultant 4N
Φ 3N φ < 900
VECTORS AT RIGHT ANGLES
Y
3N 3N R
4N X 4N
R2 = X2 + Y2 = 42 + 32 = 16 + 9 = 25
R = √ 25 = 5N
Tan θ = Y/X
θ = tan-1 (Y /X) = tan-1 (3/4)
θ = tan-1 (0.75)
θ = 36.90
R R
RESOLUTION OF VECTORS
A single vector can be resolved into two vectors called components. A vector F represented as the diagonalof the parallelogram can be resolved into its component later taken as the adjacent sides of the parallelogram.
F Y
X
sin θ = Y /F
Y = F sin θ (vertical component)
cos θ = X /F
X = F cos θ (horizontal component)
The direction of F is given by
Tan θ = Y/X
Θ = tan-1 (Y/X)
THE RESULATNT OF MORE THAN TWO VECTORS
To find the resultant of more than two vectors, we resolve each vector in two perpendicular direction s add all the horizontal components X, and all the vertical components, Y.
For example, consider four forces acting on a body as shown below
F2 F1 Y
Θ2 θ1
Θ3 θ4
X
Add all the resolved horizontal components
X = F1 cos θ1 + (-F2 cosθ2 ) + (-F3 cos θ3 ) + F4 cos θ4
Y= F1 sin θ1 + F2 sinθ2 + (-F3 sinθ3) + (-F4 sinθ4)
R = √X2+ Y2
And the direction ∞ is given by
Tan ∞ = y/x
EVALUATION
1 Calculate the resultant of five coplanar forces of values10N, 12N , 16N , 20N , 15N on an object as shown below
20N 12N
40 O 500
30O10N
16N 15N
F(N) inclination Hor.comp. Vert. comp.
10 0 10cos θ=10.00 10 sin θ= 0
12 50 12 cos 50 =7.71 12 sin50= 9.19
20 40 -20 cos 40 =-15.32 20sin40= 12.85
16 90 16 cos 90 = 0 -16 sin 90= -16.00
15 60 15cos60 =7.50 -15 sin60 =-12.99
9.89 -6.95
R = √(19.892 + (6.952
R = 12.09
Tan ∞ = 6.95/9.89
∞ = -35.10 54.9
90 – 35.1
=54.9
The direction of the resultant is S 54.90
GENERAL EVALAUTION
WEEKEND ASSIGNMENT
(d) acceleration (e) Electric field
(e) temperature
makes an angle of 60 with the resultant , calculate its magnitude
(sin60 = 0.8660 ,cos 60 = 0.500) (a) 200N (b) 173.2N (c) 115 .5N (d) 86.6 N
horizontal .If the effective force pulling the toy along the tension in rope (a) 2.5 N (b) 4.33N (c) 5.0 N (d) 8.66N (e) 10.0N
If the tension in the lift the load off the ground is ( sin 30 = ½ , cos 30 = √3/2 and tan30 = 1/√3 ) (a) 255N (b) 202.5N (c) 105 √3/2 N (d) 75N (e) 52.5N
THEORY
400 600
300 15N
Calculate their resultant
READING ASSIGNMENT
New Sch. Physics for Senior Sec. Schls. Pages 346---356
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