SUBJECT: MATHEMATICS
CLASS: JSS 3
DATE:
TERM: 2nd TERM
TOPIC: SCALE DRAWING Using Scales A scale is a ratio or proportion that shows the relationship between a length or a drawing and the corresponding length on the actual object. Thus, Scale = Any length on scale drawing Corresponding length on actual object Worked Examples actual length of the billboard if the scale is 1cm represents 2m? Solution 1cm represents 2m 5cm represents 5 × 2m = 10m The actual length of the billboard = 10m. length on the drawing. Solution 500m is represented by 1cm 1m is represented by 1/500cm 6000m is represented by 6000 × 1/500 = 12cm Length on drawing = 12cm Evaluation: Actual length Scale Length on drawing 20m 1cm to 5m 450m 1cm to 100m 65m 1cm to 5m Length on drawing Scale Actual length 11cm 1cm to 5m 8.2cm 1cm to 100m 12.6cm 2cm to 1m Scale Drawing Scale drawing is very important to engineers, architects, surveyors and navigators. For an accurate scale drawing, mathematical instruments are needed such as pencils, a ruler and a set-square. Also, the dimensions of the actual objects are written on the drawing. Worked Examples Solution Firstly, make a rough sketch of the plan 45m 30m Secondly, choose a suitable scale Using 1cm represent5m will give a 9cm by 6cm rectangle. The distance between the opposite corners of the field is represented by the dotted line. Length of the dotted line = 10.75 Actual distance = 10.75 × 5 = 53.75m = 54m (to the nearest metre) Example 2: Points A and B are 178m and 124m from X respectively. The distance between A and B is 108m. Make a scale drawing of the path and find the angle between the paths and X. X Solution 178m 124m A B 108m Using a suitable scale of 1cm to 20m, the sides of the triangle in scale drawing will be as follows: AX = 178/20 = 8.9cm, BX = 124/20 = 6.2cm, AB = 108/20 = 5.4cm. X 178m 124m A 108m B Using a protractor, AXB = 370 (to the nearest degree). The angle between the paths is 370. Evaluation: Application of Scale Drawing on Related Problems Worked Examples Solution Note: Map scale = actual distance/distance on the map. ∴ Distance on map = Actual distance / Map Scale 5.5cm represent 50,000 × 5.5 = 275,000cm To correct to km = 275,000/100,000 = 2.75km. 4km = 100,000 × 4 = 400,000cm. Since 50,000cm represents 1cm 400,000cm is represented by 400,000/50,000 = 8cm or Distance on the map = Actual distance / Map Scale = 400,000 / 50,000 = 8cm. Example 2: Two cities are 70km apart. The distance between them is 20cm on the map. What is the scale of the map? Solution 1km = 100,000cm ∴ 70km = 100,000 × 70 = 7,000,000cm Map scale = actual distance/distance on map. = 7,000,000/20 = 350,000 The scale of the map = 1 : 350,000. Evaluation: Class Work by a) 5cm b) 10cm READING ASSIGNMENT: NGM Bk 2 Chapter 16, Pages 133 – 134. Essential Mathematics for JSS Bk 2, Chapter 17, Pg 166 – 169 WEEKEND ASSIGNMENT polygon has. a) 11 b) 21 c) 16 d) 13 QR = 3cm and TQ = 4cm, what is PS? rhombus? a) 8cm b) 7cm c) 10cm d) 5cm THEORY 1.The scale on the map is 2cm : 30,000km Find the distance in km between two islands represented by a distance of 20cm on the
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