Lesson Notes By Weeks and Term - Junior Secondary School 3

SCALE DRAWING

SUBJECT: MATHEMATICS

CLASS:  JSS 3

DATE:

TERM: 2nd TERM

 

 
WEEK TEN                                          DATE---------------

TOPIC: SCALE DRAWING

Using Scales

A scale is a ratio or proportion that shows the relationship between a length or a drawing and the corresponding length on the actual object.

Thus,

    Scale = Any length on scale drawing

                  Corresponding length on actual object

 

Worked Examples

  1. The scale drawing of the length of an advertisement billboard measures 5cm. What is the 

             actual length of the billboard if the scale is 1cm represents 2m?

    Solution

    1cm represents 2m

    5cm represents 5 × 2m = 10m

    The actual length of the billboard = 10m.

  1. An airport runway measuring 6000m is drawn to a scale of 1cm represents 500m. Find its 

    length on the drawing.

    Solution

    500m is represented by 1cm

    1m is represented by 1/500cm

    6000m is represented by 6000 × 1/500 = 12cm

    Length on drawing = 12cm

 

Evaluation: 

  1. Copy and complete the table below in finding the length on drawing giving a suitable scale.

Actual length

Scale

Length on drawing

20m

1cm to 5m

 

450m

1cm to 100m

 

65m

1cm to 5m

 

 

  1.   Copy and complete the table by finding the actual length.

Length on drawing

Scale

Actual length

11cm

1cm to 5m

 

8.2cm

1cm to 100m

 

12.6cm

2cm to 1m

 

 

Scale Drawing

Scale drawing is very important to engineers, architects, surveyors and navigators. For an accurate scale drawing, mathematical instruments are needed such as pencils, a ruler and a set-square. Also, the dimensions of the actual objects are written on the drawing.

 

Worked Examples

  1. A rectangular field measures 45m by 30m. Draw a plan of the field. Use measurement to find the distance between opposite corners of the field.

Solution

Firstly, make a rough sketch of the plan

                                        45m       

    30m





Secondly, choose a suitable scale

Using 1cm represent5m will give a 9cm by 6cm rectangle.

The distance between the opposite corners of the field is represented by the dotted line. Length of the dotted line = 10.75

Actual distance = 10.75 × 5 = 53.75m = 54m (to the nearest metre)

Example 2: 

Points A and B are 178m and 124m from X respectively. The distance between A and B is 108m. Make a scale drawing of the path and find the angle between the paths and X.             X

Solution                         178m               124m




   

                              A                            B

                                        108m               

Using a suitable scale of 1cm to 20m, the sides of the triangle in scale drawing will be as follows:

AX = 178/20 = 8.9cm, BX = 124/20 = 6.2cm, AB = 108/20 = 5.4cm.

    X






                           178m                     124m 






                     A         108m             B          

Using a protractor, AXB = 370 (to the nearest degree). The angle between the paths is 370.

 

Evaluation: 

  1. Find the distance between the opposite corners of a rectangular room which is 12m by 9m. Use a scale of 1cm to 3m.
  2. A triangular plot ABC is such that AB = 120m, BC = 80m and CA = 60m. P is the middle point of AB. Find the length of PC. Use a scale of 1cm to 10m.

 

Application of Scale Drawing on Related Problems

Worked Examples

  1. The scale on a map is 1 : 50,000.
    1. Two villages A and B on the map are 5.5cm apart, find the actual distance in km between A and B.
    2. If town C is 4km from the village A, what is the distance of C from A on the map?

Solution

Note: Map scale = actual distance/distance on the map.

Distance on map = Actual distance / Map Scale

  1. 1cm represents 50,000cm

5.5cm represent 50,000 × 5.5 = 275,000cm

To correct to km = 275,000/100,000 = 2.75km.

  1. 1km = 100,000cm

4km = 100,000 × 4 = 400,000cm.

Since 50,000cm represents 1cm

400,000cm is represented by 400,000/50,000 = 8cm

or Distance on the map = Actual distance / Map Scale

            = 400,000 / 50,000 = 8cm.

Example 2: 

Two cities are 70km apart. The distance between them is 20cm on the map. What is the scale of the map?

Solution

1km = 100,000cm

70km = 100,000 × 70 = 7,000,000cm

Map scale = actual distance/distance on map.

    = 7,000,000/20 = 350,000

The scale of the map = 1 : 350,000.

 

Evaluation: Class Work

  1. The scale on the map is 1 : 25,000.
  2. a) Find the distance in km between two islands represented by a distance of 20cm on the map.
  3. b) Find the distance between two towns on the map that are 10km apart..
  4. The scale of a map is 1 : 20,000. Find the actual distance in km represented by the map   

       by    a) 5cm          b) 10cm

 

READING ASSIGNMENT:

NGM Bk 2 Chapter 16, Pages 133 – 134.

Essential Mathematics for JSS Bk 2, Chapter 17, Pg 166 – 169

 

WEEKEND ASSIGNMENT

  1. A quadrilateral has angles of 1280, 910, a0 and 2a0. Find the value of a0.
  2. a) 670 b) 470    c) 570    d) 1070
  3. The sum of the angles of a polygon is 16200, calculate the number of sides that the  

       polygon has.  a) 11    b) 21    c) 16    d) 13

  1. In fig. 1, PQRT and TQRS are parallelogram

    QR = 3cm and TQ = 4cm, what is PS?

  1. Which of the following are Pythagoras triple?  I (3, 4, 5) II (5, 12, 13)    III (8, 13, 17).
  2. a) III only b) I and II only        c) II only      d) II and III only.
  3. The diagonals of a rhombus measures 8cm y 6cm, what is the length of a side of the 

rhombus?    a) 8cm     b) 7cm     c) 10cm     d) 5cm

 

THEORY

1.The scale on the map is 2cm : 30,000km

Find the distance in km between two islands represented by a distance of 20cm on the 

  1. A map of Nigeria shows scale of 1cm representing 75km. how far is it from Ibadan to kano, if the route distance measures 30.5cm on the map


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