SUBJECT: MATHEMATICS
CLASS: JSS 2
DATE:
TERM: 3rd TERM
REFERENCE
WEEK TWO
TOPIC: ANGLES IN POLYGON
CONTENT: (i) Sum of interior angles of a polygon
(ii) Sum of exterior angles of a polygon
DEFINITION OF A POLYGON
A polygon is any close plane figure with straight side. A regular polygon has all sides and angles equal.
Polygon are named according to the number of sides they have. Examples are:
Triangle a 3- sided polygon
Quadrilateral a 4- sided polygon
Pentagon a 5- sided polygon
Hexagon a 6- sided polygon
Heptagon a 7- sided polygon
Octagon a 8- sided polygon
Nonagon a 9- sided polygon
Decagon a 10- sided polygon
The diagrams below represent some common polygons.
Triangle Quadrilateral Pentagon Hexagon
(3 sided) (4- sided) (5- sided) (6- sided)
Reference
NGM Book 2
Essential Mathematics for junior secondary school Book 2, chapter 9, pages 87 – 88
Sum of Interior Angles of a Polygon
The angles inside a polygon are called its interior angles as shown in the figure below:
e = exterior angle
i = interior angle
The number of triangles depends on the number of sides of the polygon. For a polygon with ‘n’ sides there will be (n-2) triangles. The sum of angles of a triangle is 1800.
Alternatively, since 1800 = (n-2) x 2 x 90
= 2(n-2) 90
= (2n-4) 90
Thus, the sum of the angles of an n-sided polygon can be represented as (n-2) 1800 or (2n-4) 900
The table below shows the sum of interior angles of a regular polygon of a 3 sided polygon up to a sided polygon.
Polygon | No. of Sides | No. of Triangles (n-2) | Sum of interior Angles (n-2) 1800 |
Triangle | 3 | 3 – 2 = 1 | 1 x 1800 = 180 |
Quadrilateral | 4 | 4 – 2 = 2 | 2 x 1800 = 3600 |
Pentagon | 5 | 5 – 2 = 3 | 3 x 1800 = 5400 |
Hexagon | 6 | 6 – 2 = 4 | 4 x 1800 = 7200 |
Heptagon | 7 | 7 – 2 = 5 | 5 x 1800 = 9000 |
Octagon | 8 | 8 – 2 = 6 | 6 x 1800 = 10800 |
Nonagon | 9 | 9 – 2 = 7 | 7 x 1800 = 12600 |
Decagon | 10 | 10 – 2 = 8 | 8 x 1800 = 14400 |
Worked Examples:
Answer to the evaluation questions
Size of each exterior angle = sum of exterior angles/number of sides.
= 360°9
= 40o
Hexagon has 6 sides.
Size of each exterior angle = sum of exterior anlgesno of sides
= 360°6=60o
GENERAL EVALUATION
REVISION QUESTION
READING ASSIGNMENT
Essential Mathematics for junior secondary school Book 2, Chapter 19, page 252 - 255
Exercise 19.5 No 1 page 255
WEEKEND ASSIGNMENT
THEORY
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