Worked Example 1
Scenario
Solve the polynomial equation x^3 - 6x^2 + 11x - 6 = 0 using factoring and the Rational Root Theorem.
Explanation
First, list possible rational roots using factors of the constant term (±1, ±2, ±3, ±6). Test these roots by substitution or synthetic division. Testing x=1: 1 - 6 + 11 - 6 = 0, so x=1 is a root. Divide the polynomial by (x - 1) using synthetic division to get x^2 - 5x + 6. Factor the quadratic as (x - 2)(x - 3). So the solutions are x=1, x=2, and x=3.
Answer Guide
The solutions to the equation are x = 1, x = 2, and x = 3.
Worked Example 2
Scenario
Solve the polynomial inequality x^3 - 4x^2 - 7x + 10 > 0 and express the solution set in interval notation.
Explanation
First, solve the related equation x^3 - 4x^2 - 7x + 10 = 0 to find critical points. Possible rational roots are ±1, ±2, ±5, ±10. Testing x=1: 1 - 4 - 7 + 10 = 0, so x=1 is a root. Use synthetic division to factor out (x - 1), resulting in x^2 - 3x - 10. Factor quadratic as (x - 5)(x + 2). Roots are x = 1, 5, and -2. These points divide the number line into intervals: (-∞, -2), (-2, 1), (1, 5), and (5, ∞). Test a point in each interval in the inequality to determine where it is true. The solution set is (-∞, -2) ∪ (1, 5).
Answer Guide
The solution set is (-∞, -2) ∪ (1, 5).
Worked Example 3
Scenario
Solve the rational inequality (x + 2)/(x - 3) ≤ 0 and write the solution set in interval notation.
Explanation
Find critical points by setting numerator and denominator equal to zero: numerator zero at x = -2, denominator zero at x = 3 (excluded). These points divide the number line into intervals: (-∞, -2), (-2, 3), and (3, ∞). Test points in each interval: For x = -3, ( -3 + 2 ) / ( -3 - 3 ) = (-1)/(-6) = positive, so inequality false. For x = 0, (0 + 2)/(0 - 3) = 2/(-3) = negative, inequality true. For x = 4, (4 + 2)/(4 - 3) = 6/1 = positive, inequality false. Include x = -2 since numerator zero makes expression zero, which satisfies ≤ 0. Exclude x = 3 since denominator zero is undefined. Solution set is [-2, 3).
Answer Guide
The solution set is [-2, 3).
Worked Example 4
Scenario
Given the polynomial inequality x^4 - 5x^2 + 4 ≤ 0, find the solution set and explain your reasoning.
Explanation
Rewrite as (x^2)^2 - 5(x^2) + 4 ≤ 0. Let y = x^2, so inequality becomes y^2 - 5y + 4 ≤ 0. Factor as (y - 4)(y - 1) ≤ 0. The critical points are y = 1 and y = 4. Since y = x^2 ≥ 0, consider intervals for y: [0,1], [1,4], and [4,∞). Test values: For y=0.5, product is negative (true). For y=2, product is negative (true). For y=5, product is positive (false). So solution for y is [1,4]. Convert back to x: x^2 ∈ [1,4], so x ∈ [-2,-1] ∪ [1,2].
Answer Guide
The solution set is [-2, -1] ∪ [1, 2].
Worked Example 5
Scenario
A company models profit P(x) with the rational function P(x) = (x^2 - 9)/(x - 4). Determine where the profit is positive and express the solution in interval notation.
Explanation
Set inequality (x^2 - 9)/(x - 4) > 0. Factor numerator: (x - 3)(x + 3). Critical points are x = 3, x = -3 (numerator zeros), and x = 4 (denominator zero, excluded). Intervals: (-∞, -3), (-3, 3), (3, 4), (4, ∞). Test points: x = -4 → numerator positive, denominator negative → negative (false). x=0 → numerator negative, denominator negative → positive (true). x=3.5 → numerator positive, denominator negative → negative (false). x=5 → numerator positive, denominator positive → positive (true). Solution set: (-3, 3) ∪ (4, ∞).
Answer Guide
The profit is positive on the intervals (-3, 3) and (4, ∞).